问题标题:
帮我解答几个数学分解因式……20我们目前学到提取公因式、公式法、十字相乘法、分组分解式x2-10x-24a2b2-ab-20x2+25xy+150y2x4-5x2y2-36y4x2y2-x2-y2+1(x2-x)2-18(x2-x)+72(x+1)(x+2)-x-10a2-2ab+b2-3a+3b
问题描述:
帮我解答几个数学分解因式……20
我们目前学到提取公因式、公式法、十字相乘法、分组分解式
x2-10x-24
a2b2-ab-20
x2+25xy+150y2
x4-5x2y2-36y4
x2y2-x2-y2+1
(x2-x)2-18(x2-x)+72
(x+1)(x+2)-x-10
a2-2ab+b2-3a+3b-10
x2-3xy-18y2-3x-9y
字母后面的数字是平方、立方或者四次方……注意咯.送分.
涂奉生回答:
x2-10x-24
=(x-12)(x+2)
a2b2-ab-20
=(ab-5)(ab+4)
x2+25xy+150y2
=(x+15y)(x+10y)
x4-5x2y2-36y4
=(x^2-9y^2)(x^2+4y^2)
=(x+3y)(x-3y)(x^2+4y^2)
x2y2-x2-y2+1
=x^2(y^2-1)-(y^2-1)
=(y^2-1)(x^2-1)
=(y+1)(y-1)(x+1)(x-1)
(x2-x)2-18(x2-x)+72
=(x^2-x-12)(x^2-x-6)
=(x-4)(x+3)(x-3)(x+2)
(x+1)(x+2)-x-10
=x^2+3x+2-x-10
=x^2+2x-8
=(x+4)(x-2)
a2-2ab+b2-3a+3b-10
=(a-b)^2-3(a-b)-10
=(a-b-5)(a-b+2)
x2-3xy-18y2-3x-9y
=(x-6y)(x+3y)-3(x+3y)
=(x+3y)(x-6y-3)
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