问题标题:
发射卫星用N2H4为燃料,NO2为氧化剂,两者反应生成N2和水蒸气,已知N2(g)+2O2(g)=2NO2(g)△H1=+67.7kJ/mol;N2H4(g)+O2(g)=N2(g)+2H2O(g)△H2=-534kJ/mol;2H2(g)+O2(g)=2H2O(g)△H3=-484kJ/m
问题描述:
发射卫星用N2H4为燃料,NO2为氧化剂,两者反应生成N2和水蒸气,已知
N2(g)+2O2(g)=2NO2(g)△H1=+67.7kJ/mol;
N2H4(g)+O2(g)=N2(g)+2H2O(g)△H2=-534kJ/mol;
2H2(g)+O2(g)=2H2O(g)△H3=-484kJ/mol;
H2(g)+F2(g)=2HF(g)△H4=-538kJ/mol
(1)写出N2H4与 NO2反应的热化学方程式______,
(2)写出N2H4与F2反应的热化学方程式______.
焦毅回答:
发射卫星用N2H4为燃料,NO2为氧化剂,两者反应生成N2和水蒸气,已知①N2(g)+2O2(g)=2NO2(g)△H1=+67.7kJ/mol;②N2H4(g)+O2(g)=N2(g)+2H2O(g)△H2=-534kJ/mol;③2H2(g)+O2(g)=2H2O(g)△H3=-484...
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